X^2-48x-1024=0

Solution for X^2-48x-1024=0 equation:

X^2-48X-1024=0

a = 1; b = -48; c = -1024;
Δ = b2-4ac
Δ = -482-4·1·(-1024)
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400}=80$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-80}{2*1}=\frac{-32}{2}
=-16
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+80}{2*1}=\frac{128}{2}
=64
$